Solve y=2/3+x

$$y= \frac{ 2 }{ 3+x }$$

Solve for x

$$x=-3+\frac{2}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.

$$y\left(x+3\right)=2$$

Use the distributive property to multiply y by x+3.

$$yx+3y=2$$

Subtract 3y from both sides.

$$yx=2-3y$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{2-3y}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{2-3y}{y}$$

Divide 2-3y by y.

$$x=-3+\frac{2}{y}$$

Variable x cannot be equal to -3.

$$x=-3+\frac{2}{y}\text{, }x\neq -3$$

Solve for y

$$y=\frac{2}{x+3}$$

$$x\neq -3$$