Solve for y
y=\frac{\left(x-6\right)^{2}+3}{3}
Solve for x (complex solution)
x=-\sqrt{3\left(y-1\right)}+6
x=\sqrt{3\left(y-1\right)}+6
Solve for x
x=-\sqrt{3\left(y-1\right)}+6
x=\sqrt{3\left(y-1\right)}+6\text{, }y\geq 1
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y=\frac{1}{3}\left(x^{2}-12x+36\right)+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-6\right)^{2}.
y=\frac{1}{3}x^{2}-4x+12+1
Use the distributive property to multiply \frac{1}{3} by x^{2}-12x+36.
y=\frac{1}{3}x^{2}-4x+13
Add 12 and 1 to get 13.
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