Solve y=-3x+2/2

$$y= \frac{ -3x+2 }{ 2 }$$

Solve for x

$$x=\frac{2-2y}{3}$$

Steps for Solving Linear Equation

Divide each term of -3x+2 by 2 to get -\frac{3}{2}x+1.

$$y=-\frac{3}{2}x+1$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{3}{2}x+1=y$$

Subtract 1 from both sides.

$$-\frac{3}{2}x=y-1$$

Divide both sides of the equation by -\frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{2}x}{-\frac{3}{2}}=\frac{y-1}{-\frac{3}{2}}$$

Dividing by -\frac{3}{2} undoes the multiplication by -\frac{3}{2}.

$$x=\frac{y-1}{-\frac{3}{2}}$$

Divide y-1 by -\frac{3}{2} by multiplying y-1 by the reciprocal of -\frac{3}{2}.

$$x=\frac{2-2y}{3}$$

Solve for y

$$y=-\frac{3x}{2}+1$$

Solution Steps

Divide each term of -3x+2 by 2 to get -\frac{3}{2}x+1.

$$y=-\frac{3}{2}x+1$$