Solve y+2=8/9(x-5)

$$y+2= \frac{ 8 }{ 9 } (x-5)$$

Solve for x

$$x=\frac{9y}{8}+\frac{29}{4}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{8}{9} by x-5.

$$y+2=\frac{8}{9}x-\frac{40}{9}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{8}{9}x-\frac{40}{9}=y+2$$

Add \frac{40}{9} to both sides.

$$\frac{8}{9}x=y+2+\frac{40}{9}$$

Add 2 and \frac{40}{9} to get \frac{58}{9}.

$$\frac{8}{9}x=y+\frac{58}{9}$$

Divide both sides of the equation by \frac{8}{9}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{8}{9}x}{\frac{8}{9}}=\frac{y+\frac{58}{9}}{\frac{8}{9}}$$

Dividing by \frac{8}{9} undoes the multiplication by \frac{8}{9}.

$$x=\frac{y+\frac{58}{9}}{\frac{8}{9}}$$

Divide y+\frac{58}{9} by \frac{8}{9} by multiplying y+\frac{58}{9} by the reciprocal of \frac{8}{9}.

$$x=\frac{9y}{8}+\frac{29}{4}$$

Solve for y

$$y=\frac{8x-58}{9}$$

Solution Steps

Use the distributive property to multiply \frac{8}{9} by x-5.

$$y+2=\frac{8}{9}x-\frac{40}{9}$$

Subtract 2 from both sides.

$$y=\frac{8}{9}x-\frac{40}{9}-2$$

Subtract 2 from -\frac{40}{9} to get -\frac{58}{9}.

$$y=\frac{8}{9}x-\frac{58}{9}$$