Solve y+1=-2/3x+2/3

$$y+1=- \frac{ 2 }{ 3 } x+ \frac{ 2 }{ 3 }$$

Solve for x

$$x=\frac{-3y-1}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}x+\frac{2}{3}=y+1$$

Subtract \frac{2}{3} from both sides.

$$-\frac{2}{3}x=y+1-\frac{2}{3}$$

Subtract \frac{2}{3} from 1 to get \frac{1}{3}.

$$-\frac{2}{3}x=y+\frac{1}{3}$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y+\frac{1}{3}}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y+\frac{1}{3}}{-\frac{2}{3}}$$

Divide y+\frac{1}{3} by -\frac{2}{3} by multiplying y+\frac{1}{3} by the reciprocal of -\frac{2}{3}.

$$x=\frac{-3y-1}{2}$$

Solve for y

$$y=\frac{-2x-1}{3}$$

Solution Steps

Subtract 1 from both sides.

$$y=-\frac{2}{3}x+\frac{2}{3}-1$$

Subtract 1 from \frac{2}{3} to get -\frac{1}{3}.

$$y=-\frac{2}{3}x-\frac{1}{3}$$