Solve y_{0}=4*(-1/8)^2+1/8-3

$$y _ { 0 } = 4 \cdot ( \frac { - 1 } { 8 } ) ^ { 2 } + \frac { 1 } { 8 } - 3$$

Solve for y_0

$$y_{0} = -\frac{45}{16} = -2\frac{13}{16} = -2.8125$$

Steps for Solving Linear Equation

Fraction \frac{-1}{8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$y_{0}=4\left(-\frac{1}{8}\right)^{2}+\frac{1}{8}-3$$

Calculate -\frac{1}{8} to the power of 2 and get \frac{1}{64}.

$$y_{0}=4\times \frac{1}{64}+\frac{1}{8}-3$$

Multiply 4 and \frac{1}{64} to get \frac{1}{16}.

$$y_{0}=\frac{1}{16}+\frac{1}{8}-3$$

Add \frac{1}{16} and \frac{1}{8} to get \frac{3}{16}.

$$y_{0}=\frac{3}{16}-3$$

Subtract 3 from \frac{3}{16} to get -\frac{45}{16}.

$$y_{0}=-\frac{45}{16}$$

Assign y_0

$$y_{0}≔-\frac{45}{16}$$