Solve y-8x^2=12

$$y - 8 x ^ { 2 } = 12$$

Solve for y

$$y=8x^{2}+12$$

Solution Steps

Add 8x^{2} to both sides.

$$y=12+8x^{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{2\left(y-12\right)}}{4}$$

$$x=\frac{\sqrt{2\left(y-12\right)}}{4}$$

Solve for x

$$x=\frac{\sqrt{2\left(y-12\right)}}{4}$$

$$x=-\frac{\sqrt{2\left(y-12\right)}}{4}\text{, }y\geq 12$$