Solve y-7=10,5-7/4,5-3(x-3)

$$y - 7 = \frac { 10,5 - 7 } { 4,5 - 3 } ( x - 3 )$$

Solve for x

$$x=\frac{3y}{7}$$

Steps for Solving Linear Equation

Subtract 7 from 10,5 to get 3,5.

$$y-7=\frac{3,5}{4,5-3}\left(x-3\right)$$

Subtract 3 from 4,5 to get 1,5.

$$y-7=\frac{3,5}{1,5}\left(x-3\right)$$

Expand \frac{3,5}{1,5} by multiplying both numerator and the denominator by 10.

$$y-7=\frac{35}{15}\left(x-3\right)$$

Reduce the fraction \frac{35}{15} to lowest terms by extracting and canceling out 5.

$$y-7=\frac{7}{3}\left(x-3\right)$$

Use the distributive property to multiply \frac{7}{3} by x-3.

$$y-7=\frac{7}{3}x-7$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{7}{3}x-7=y-7$$

Add 7 to both sides.

$$\frac{7}{3}x=y-7+7$$

Add -7 and 7 to get 0.

$$\frac{7}{3}x=y$$

Divide both sides of the equation by \frac{7}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{3}x}{\frac{7}{3}}=\frac{y}{\frac{7}{3}}$$

Dividing by \frac{7}{3} undoes the multiplication by \frac{7}{3}.

$$x=\frac{y}{\frac{7}{3}}$$

Divide y by \frac{7}{3} by multiplying y by the reciprocal of \frac{7}{3}.

$$x=\frac{3y}{7}$$

Solve for y

$$y=\frac{7x}{3}$$

Solution Steps

Subtract 7 from 10,5 to get 3,5.

$$y-7=\frac{3,5}{4,5-3}\left(x-3\right)$$

Subtract 3 from 4,5 to get 1,5.

$$y-7=\frac{3,5}{1,5}\left(x-3\right)$$

Expand \frac{3,5}{1,5} by multiplying both numerator and the denominator by 10.

$$y-7=\frac{35}{15}\left(x-3\right)$$

Reduce the fraction \frac{35}{15} to lowest terms by extracting and canceling out 5.

$$y-7=\frac{7}{3}\left(x-3\right)$$

Use the distributive property to multiply \frac{7}{3} by x-3.

$$y-7=\frac{7}{3}x-7$$

Add 7 to both sides.

$$y=\frac{7}{3}x-7+7$$

Add -7 and 7 to get 0.

$$y=\frac{7}{3}x$$