Solve y-2=4/3x+12

$$y - 2 = \frac { 4 } { 3 } x + 12$$

Solve for x

$$x=\frac{3\left(y-14\right)}{4}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{3}x+12=y-2$$

Subtract 12 from both sides.

$$\frac{4}{3}x=y-2-12$$

Subtract 12 from -2 to get -14.

$$\frac{4}{3}x=y-14$$

Divide both sides of the equation by \frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{3}x}{\frac{4}{3}}=\frac{y-14}{\frac{4}{3}}$$

Dividing by \frac{4}{3} undoes the multiplication by \frac{4}{3}.

$$x=\frac{y-14}{\frac{4}{3}}$$

Divide y-14 by \frac{4}{3} by multiplying y-14 by the reciprocal of \frac{4}{3}.

$$x=\frac{3y}{4}-\frac{21}{2}$$

Solve for y

$$y=\frac{4x}{3}+14$$

Solution Steps

Add 2 to both sides.

$$y=\frac{4}{3}x+12+2$$

Add 12 and 2 to get 14.

$$y=\frac{4}{3}x+14$$