Solve y-1=4(3(x-4))

$$y - 1 = 4 ( 3 ( x - 4 ) )$$

Solve for x

$$x=\frac{y+47}{12}$$

Steps for Solving Linear Equation

Multiply 4 and 3 to get 12.

$$y-1=12\left(x-4\right)$$

Use the distributive property to multiply 12 by x-4.

$$y-1=12x-48$$

Swap sides so that all variable terms are on the left hand side.

$$12x-48=y-1$$

Add 48 to both sides.

$$12x=y-1+48$$

Add -1 and 48 to get 47.

$$12x=y+47$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{y+47}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{y+47}{12}$$

Solve for y

$$y=12x-47$$

Solution Steps

Multiply 4 and 3 to get 12.

$$y-1=12\left(x-4\right)$$

Use the distributive property to multiply 12 by x-4.

$$y-1=12x-48$$

Add 1 to both sides.

$$y=12x-48+1$$

Add -48 and 1 to get -47.

$$y=12x-47$$