Solve for x
x=\frac{3y+7}{2}
Solve for y
y=\frac{2x-7}{3}
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y-1=\frac{2}{3}x-\frac{10}{3}
Use the distributive property to multiply \frac{2}{3} by x-5.
\frac{2}{3}x-\frac{10}{3}=y-1
Swap sides so that all variable terms are on the left hand side.
\frac{2}{3}x=y-1+\frac{10}{3}
Add \frac{10}{3} to both sides.
\frac{2}{3}x=y+\frac{7}{3}
Add -1 and \frac{10}{3} to get \frac{7}{3}.
\frac{\frac{2}{3}x}{\frac{2}{3}}=\frac{y+\frac{7}{3}}{\frac{2}{3}}
Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+\frac{7}{3}}{\frac{2}{3}}
Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.
x=\frac{3y+7}{2}
Divide y+\frac{7}{3} by \frac{2}{3} by multiplying y+\frac{7}{3} by the reciprocal of \frac{2}{3}.
y-1=\frac{2}{3}x-\frac{10}{3}
Use the distributive property to multiply \frac{2}{3} by x-5.
y=\frac{2}{3}x-\frac{10}{3}+1
Add 1 to both sides.
y=\frac{2}{3}x-\frac{7}{3}
Add -\frac{10}{3} and 1 to get -\frac{7}{3}.
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