Solve y-1=1/3(x+3)

$$y - 1 = \frac { 1 } { 3 } ( x + 3 )$$

Solve for x

$$x=3\left(y-2\right)$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{3} by x+3.

$$y-1=\frac{1}{3}x+1$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+1=y-1$$

Subtract 1 from both sides.

$$\frac{1}{3}x=y-1-1$$

Subtract 1 from -1 to get -2.

$$\frac{1}{3}x=y-2$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y-2}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{y-2}{\frac{1}{3}}$$

Divide y-2 by \frac{1}{3} by multiplying y-2 by the reciprocal of \frac{1}{3}.

$$x=3y-6$$

Solve for y

$$y=\frac{x+6}{3}$$

Solution Steps

Use the distributive property to multiply \frac{1}{3} by x+3.

$$y-1=\frac{1}{3}x+1$$

Add 1 to both sides.

$$y=\frac{1}{3}x+1+1$$

Add 1 and 1 to get 2.

$$y=\frac{1}{3}x+2$$