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y\times \frac{1}{8}x=3-3y
Subtract 3y from both sides.
\frac{y}{8}x=3-3y
The equation is in standard form.
\frac{8\times \frac{y}{8}x}{y}=\frac{8\left(3-3y\right)}{y}
Divide both sides by \frac{1}{8}y.
x=\frac{8\left(3-3y\right)}{y}
Dividing by \frac{1}{8}y undoes the multiplication by \frac{1}{8}y.
x=-24+\frac{24}{y}
Divide 3-3y by \frac{1}{8}y.
\left(\frac{1}{8}x+3\right)y=3
Combine all terms containing y.
\left(\frac{x}{8}+3\right)y=3
The equation is in standard form.
\frac{\left(\frac{x}{8}+3\right)y}{\frac{x}{8}+3}=\frac{3}{\frac{x}{8}+3}
Divide both sides by \frac{1}{8}x+3.
y=\frac{3}{\frac{x}{8}+3}
Dividing by \frac{1}{8}x+3 undoes the multiplication by \frac{1}{8}x+3.
y=\frac{24}{x+24}
Divide 3 by \frac{1}{8}x+3.