Solve for x
x=\frac{y^{4}-4}{3}
Solve for y (complex solution)
y=i\sqrt[4]{3x+4}
y=\sqrt[4]{3x+4}
y=-\sqrt[4]{3x+4}
y=-i\sqrt[4]{3x+4}
Solve for y
y=\sqrt[4]{3x+4}
y=-\sqrt[4]{3x+4}\text{, }x\geq -\frac{4}{3}
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-3x=4-y^{4}
Subtract y^{4} from both sides.
\frac{-3x}{-3}=\frac{4-y^{4}}{-3}
Divide both sides by -3.
x=\frac{4-y^{4}}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{y^{4}-4}{3}
Divide -y^{4}+4 by -3.
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