Solve for x
x=\frac{8-y^{4}}{7}
Solve for y (complex solution)
y=i\sqrt[4]{8-7x}
y=\sqrt[4]{8-7x}
y=-\sqrt[4]{8-7x}
y=-i\sqrt[4]{8-7x}
Solve for y
y=\sqrt[4]{8-7x}
y=-\sqrt[4]{8-7x}\text{, }x\leq \frac{8}{7}
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7x=8-y^{4}
Subtract y^{4} from both sides.
\frac{7x}{7}=\frac{8-y^{4}}{7}
Divide both sides by 7.
x=\frac{8-y^{4}}{7}
Dividing by 7 undoes the multiplication by 7.
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