Solve for z
z=y^{2}+4
Solve for y
y=\sqrt{z-4}
y=-\sqrt{z-4}\text{, }z\geq 4
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-z=-4-y^{2}
Subtract y^{2} from both sides.
-z=-y^{2}-4
The equation is in standard form.
\frac{-z}{-1}=\frac{-y^{2}-4}{-1}
Divide both sides by -1.
z=\frac{-y^{2}-4}{-1}
Dividing by -1 undoes the multiplication by -1.
z=y^{2}+4
Divide -4-y^{2} by -1.
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