Solve for x
x=-\frac{\left(y-7\right)\left(y+1\right)}{8}
Solve for y (complex solution)
y=2\sqrt{4-2x}+3
y=-2\sqrt{4-2x}+3
Solve for y
y=2\sqrt{4-2x}+3
y=-2\sqrt{4-2x}+3\text{, }x\leq 2
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-6y+8x=7-y^{2}
Subtract y^{2} from both sides.
8x=7-y^{2}+6y
Add 6y to both sides.
8x=7+6y-y^{2}
The equation is in standard form.
\frac{8x}{8}=-\frac{\left(y-7\right)\left(y+1\right)}{8}
Divide both sides by 8.
x=-\frac{\left(y-7\right)\left(y+1\right)}{8}
Dividing by 8 undoes the multiplication by 8.
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