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a+b=-5 ab=1\left(-14\right)=-14
Factor the expression by grouping. First, the expression needs to be rewritten as y^{2}+ay+by-14. To find a and b, set up a system to be solved.
1,-14 2,-7
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -14.
1-14=-13 2-7=-5
Calculate the sum for each pair.
a=-7 b=2
The solution is the pair that gives sum -5.
\left(y^{2}-7y\right)+\left(2y-14\right)
Rewrite y^{2}-5y-14 as \left(y^{2}-7y\right)+\left(2y-14\right).
y\left(y-7\right)+2\left(y-7\right)
Factor out y in the first and 2 in the second group.
\left(y-7\right)\left(y+2\right)
Factor out common term y-7 by using distributive property.
y^{2}-5y-14=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
y=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\left(-14\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-\left(-5\right)±\sqrt{25-4\left(-14\right)}}{2}
Square -5.
y=\frac{-\left(-5\right)±\sqrt{25+56}}{2}
Multiply -4 times -14.
y=\frac{-\left(-5\right)±\sqrt{81}}{2}
Add 25 to 56.
y=\frac{-\left(-5\right)±9}{2}
Take the square root of 81.
y=\frac{5±9}{2}
The opposite of -5 is 5.
y=\frac{14}{2}
Now solve the equation y=\frac{5±9}{2} when ± is plus. Add 5 to 9.
y=7
Divide 14 by 2.
y=-\frac{4}{2}
Now solve the equation y=\frac{5±9}{2} when ± is minus. Subtract 9 from 5.
y=-2
Divide -4 by 2.
y^{2}-5y-14=\left(y-7\right)\left(y-\left(-2\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 7 for x_{1} and -2 for x_{2}.
y^{2}-5y-14=\left(y-7\right)\left(y+2\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
x ^ 2 -5x -14 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 5 rs = -14
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{5}{2} - u s = \frac{5}{2} + u
Two numbers r and s sum up to 5 exactly when the average of the two numbers is \frac{1}{2}*5 = \frac{5}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{5}{2} - u) (\frac{5}{2} + u) = -14
To solve for unknown quantity u, substitute these in the product equation rs = -14
\frac{25}{4} - u^2 = -14
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -14-\frac{25}{4} = -\frac{81}{4}
Simplify the expression by subtracting \frac{25}{4} on both sides
u^2 = \frac{81}{4} u = \pm\sqrt{\frac{81}{4}} = \pm \frac{9}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{5}{2} - \frac{9}{2} = -2 s = \frac{5}{2} + \frac{9}{2} = 7
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.