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y\left(y-35\right)=0
Factor out y.
y=0 y=35
To find equation solutions, solve y=0 and y-35=0.
y^{2}-35y=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-\left(-35\right)±\sqrt{\left(-35\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -35 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-\left(-35\right)±35}{2}
Take the square root of \left(-35\right)^{2}.
y=\frac{35±35}{2}
The opposite of -35 is 35.
y=\frac{70}{2}
Now solve the equation y=\frac{35±35}{2} when ± is plus. Add 35 to 35.
y=35
Divide 70 by 2.
y=\frac{0}{2}
Now solve the equation y=\frac{35±35}{2} when ± is minus. Subtract 35 from 35.
y=0
Divide 0 by 2.
y=35 y=0
The equation is now solved.
y^{2}-35y=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
y^{2}-35y+\left(-\frac{35}{2}\right)^{2}=\left(-\frac{35}{2}\right)^{2}
Divide -35, the coefficient of the x term, by 2 to get -\frac{35}{2}. Then add the square of -\frac{35}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}-35y+\frac{1225}{4}=\frac{1225}{4}
Square -\frac{35}{2} by squaring both the numerator and the denominator of the fraction.
\left(y-\frac{35}{2}\right)^{2}=\frac{1225}{4}
Factor y^{2}-35y+\frac{1225}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y-\frac{35}{2}\right)^{2}}=\sqrt{\frac{1225}{4}}
Take the square root of both sides of the equation.
y-\frac{35}{2}=\frac{35}{2} y-\frac{35}{2}=-\frac{35}{2}
Simplify.
y=35 y=0
Add \frac{35}{2} to both sides of the equation.