Solve y^2-2xy+9=0

$$y ^ { 2 } - 2 x y + 9 = 0$$

Solve for x

$$x=\frac{y}{2}+\frac{9}{2y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2xy+9=-y^{2}$$

Subtract 9 from both sides.

$$-2xy=-y^{2}-9$$

The equation is in standard form.

$$\left(-2y\right)x=-y^{2}-9$$

Divide both sides by -2y.

$$\frac{\left(-2y\right)x}{-2y}=\frac{-y^{2}-9}{-2y}$$

Dividing by -2y undoes the multiplication by -2y.

$$x=\frac{-y^{2}-9}{-2y}$$

Divide -y^{2}-9 by -2y.

$$x=\frac{y}{2}+\frac{9}{2y}$$

Solve for y (complex solution)

$$y=\sqrt{x^{2}-9}+x$$

$$y=-\sqrt{x^{2}-9}+x$$

Solve for y

$$y=\sqrt{x^{2}-9}+x$$

$$y=-\sqrt{x^{2}-9}+x\text{, }|x|\geq 3$$