Solve y^2-2x+1=0

$$y ^ { 2 } - 2 x + 1 = 0$$

Solve for x

$$x=\frac{y^{2}+1}{2}$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2x+1=-y^{2}$$

Subtract 1 from both sides.

$$-2x=-y^{2}-1$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{-y^{2}-1}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{-y^{2}-1}{-2}$$

Divide -y^{2}-1 by -2.

$$x=\frac{y^{2}+1}{2}$$

Solve for y (complex solution)

$$y=-\sqrt{2x-1}$$

$$y=\sqrt{2x-1}$$

Solve for y

$$y=\sqrt{2x-1}$$

$$y=-\sqrt{2x-1}\text{, }x\geq \frac{1}{2}$$