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\frac{9y^{2}-1}{9}
Factor out \frac{1}{9}.
\left(3y-1\right)\left(3y+1\right)
Consider 9y^{2}-1. Rewrite 9y^{2}-1 as \left(3y\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(3y-1\right)\left(3y+1\right)}{9}
Rewrite the complete factored expression.