Solve y^2=39

$$y ^ { 2 } = 39$$

Solve for y

$$y=\sqrt{39}\approx 6.244997998$$

$$y=-\sqrt{39}\approx -6.244997998$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$y=\sqrt{39} y=-\sqrt{39}$$

Steps Using the Quadratic Formula

Subtract 39 from both sides.

$$y^{2}-39=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -39 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-39\right)}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\left(-39\right)}}{2}$$

Multiply -4 times -39.

$$y=\frac{0±\sqrt{156}}{2}$$

Take the square root of 156.

$$y=\frac{0±2\sqrt{39}}{2}$$

Now solve the equation y=\frac{0±2\sqrt{39}}{2} when ± is plus.

$$y=\sqrt{39}$$

Now solve the equation y=\frac{0±2\sqrt{39}}{2} when ± is minus.

$$y=-\sqrt{39}$$

The equation is now solved.

$$y=\sqrt{39} y=-\sqrt{39}$$