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y^{2}+13y=0
Add 13y to both sides.
y\left(y+13\right)=0
Factor out y.
y=0 y=-13
To find equation solutions, solve y=0 and y+13=0.
y^{2}+13y=0
Add 13y to both sides.
y=\frac{-13±\sqrt{13^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 13 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-13±13}{2}
Take the square root of 13^{2}.
y=\frac{0}{2}
Now solve the equation y=\frac{-13±13}{2} when ± is plus. Add -13 to 13.
y=0
Divide 0 by 2.
y=-\frac{26}{2}
Now solve the equation y=\frac{-13±13}{2} when ± is minus. Subtract 13 from -13.
y=-13
Divide -26 by 2.
y=0 y=-13
The equation is now solved.
y^{2}+13y=0
Add 13y to both sides.
y^{2}+13y+\left(\frac{13}{2}\right)^{2}=\left(\frac{13}{2}\right)^{2}
Divide 13, the coefficient of the x term, by 2 to get \frac{13}{2}. Then add the square of \frac{13}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}+13y+\frac{169}{4}=\frac{169}{4}
Square \frac{13}{2} by squaring both the numerator and the denominator of the fraction.
\left(y+\frac{13}{2}\right)^{2}=\frac{169}{4}
Factor y^{2}+13y+\frac{169}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y+\frac{13}{2}\right)^{2}}=\sqrt{\frac{169}{4}}
Take the square root of both sides of the equation.
y+\frac{13}{2}=\frac{13}{2} y+\frac{13}{2}=-\frac{13}{2}
Simplify.
y=0 y=-13
Subtract \frac{13}{2} from both sides of the equation.