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Solve for y (complex solution)
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y^{2}+24y+17=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-24±\sqrt{24^{2}-4\times 17}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 24 for b, and 17 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-24±\sqrt{576-4\times 17}}{2}
Square 24.
y=\frac{-24±\sqrt{576-68}}{2}
Multiply -4 times 17.
y=\frac{-24±\sqrt{508}}{2}
Add 576 to -68.
y=\frac{-24±2\sqrt{127}}{2}
Take the square root of 508.
y=\frac{2\sqrt{127}-24}{2}
Now solve the equation y=\frac{-24±2\sqrt{127}}{2} when ± is plus. Add -24 to 2\sqrt{127}.
y=\sqrt{127}-12
Divide -24+2\sqrt{127} by 2.
y=\frac{-2\sqrt{127}-24}{2}
Now solve the equation y=\frac{-24±2\sqrt{127}}{2} when ± is minus. Subtract 2\sqrt{127} from -24.
y=-\sqrt{127}-12
Divide -24-2\sqrt{127} by 2.
y=\sqrt{127}-12 y=-\sqrt{127}-12
The equation is now solved.
y^{2}+24y+17=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
y^{2}+24y+17-17=-17
Subtract 17 from both sides of the equation.
y^{2}+24y=-17
Subtracting 17 from itself leaves 0.
y^{2}+24y+12^{2}=-17+12^{2}
Divide 24, the coefficient of the x term, by 2 to get 12. Then add the square of 12 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}+24y+144=-17+144
Square 12.
y^{2}+24y+144=127
Add -17 to 144.
\left(y+12\right)^{2}=127
Factor y^{2}+24y+144. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y+12\right)^{2}}=\sqrt{127}
Take the square root of both sides of the equation.
y+12=\sqrt{127} y+12=-\sqrt{127}
Simplify.
y=\sqrt{127}-12 y=-\sqrt{127}-12
Subtract 12 from both sides of the equation.
x ^ 2 +24x +17 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -24 rs = 17
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -12 - u s = -12 + u
Two numbers r and s sum up to -24 exactly when the average of the two numbers is \frac{1}{2}*-24 = -12. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-12 - u) (-12 + u) = 17
To solve for unknown quantity u, substitute these in the product equation rs = 17
144 - u^2 = 17
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 17-144 = -127
Simplify the expression by subtracting 144 on both sides
u^2 = 127 u = \pm\sqrt{127} = \pm \sqrt{127}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-12 - \sqrt{127} = -23.269 s = -12 + \sqrt{127} = -0.731
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
y^{2}+24y+17=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-24±\sqrt{24^{2}-4\times 17}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 24 for b, and 17 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-24±\sqrt{576-4\times 17}}{2}
Square 24.
y=\frac{-24±\sqrt{576-68}}{2}
Multiply -4 times 17.
y=\frac{-24±\sqrt{508}}{2}
Add 576 to -68.
y=\frac{-24±2\sqrt{127}}{2}
Take the square root of 508.
y=\frac{2\sqrt{127}-24}{2}
Now solve the equation y=\frac{-24±2\sqrt{127}}{2} when ± is plus. Add -24 to 2\sqrt{127}.
y=\sqrt{127}-12
Divide -24+2\sqrt{127} by 2.
y=\frac{-2\sqrt{127}-24}{2}
Now solve the equation y=\frac{-24±2\sqrt{127}}{2} when ± is minus. Subtract 2\sqrt{127} from -24.
y=-\sqrt{127}-12
Divide -24-2\sqrt{127} by 2.
y=\sqrt{127}-12 y=-\sqrt{127}-12
The equation is now solved.
y^{2}+24y+17=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
y^{2}+24y+17-17=-17
Subtract 17 from both sides of the equation.
y^{2}+24y=-17
Subtracting 17 from itself leaves 0.
y^{2}+24y+12^{2}=-17+12^{2}
Divide 24, the coefficient of the x term, by 2 to get 12. Then add the square of 12 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}+24y+144=-17+144
Square 12.
y^{2}+24y+144=127
Add -17 to 144.
\left(y+12\right)^{2}=127
Factor y^{2}+24y+144. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y+12\right)^{2}}=\sqrt{127}
Take the square root of both sides of the equation.
y+12=\sqrt{127} y+12=-\sqrt{127}
Simplify.
y=\sqrt{127}-12 y=-\sqrt{127}-12
Subtract 12 from both sides of the equation.