Solve y^2+16=7

$$y ^ { 2 } + 16 = 7$$

Solve for y

$$y=-3i$$

$$y=3i$$

Steps by Finding Square Root

Subtract 16 from both sides.

$$y^{2}=7-16$$

Subtract 16 from 7 to get -9.

$$y^{2}=-9$$

The equation is now solved.

$$y=3i y=-3i$$

Steps Using the Quadratic Formula

Subtract 7 from both sides.

$$y^{2}+16-7=0$$

Subtract 7 from 16 to get 9.

$$y^{2}+9=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 9 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\times 9}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\times 9}}{2}$$

Multiply -4 times 9.

$$y=\frac{0±\sqrt{-36}}{2}$$

Take the square root of -36.

$$y=\frac{0±6i}{2}$$

Now solve the equation y=\frac{0±6i}{2} when ± is plus.

$$y=3i$$

Now solve the equation y=\frac{0±6i}{2} when ± is minus.

$$y=-3i$$

The equation is now solved.

$$y=3i y=-3i$$