Solve y^2+10y-25-16x+6y=0

$$y ^ { 2 } + 10 y - 25 - 16 x + 6 y = 0$$

Solve for x

$$x=\frac{y^{2}}{16}+y-\frac{25}{16}$$

Steps for Solving Linear Equation

Combine 10y and 6y to get 16y.

$$y^{2}+16y-25-16x=0$$

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$16y-25-16x=-y^{2}$$

Subtract 16y from both sides.

$$-25-16x=-y^{2}-16y$$

Add 25 to both sides.

$$-16x=-y^{2}-16y+25$$

The equation is in standard form.

$$-16x=25-16y-y^{2}$$

Divide both sides by -16.

$$\frac{-16x}{-16}=\frac{25-16y-y^{2}}{-16}$$

Dividing by -16 undoes the multiplication by -16.

$$x=\frac{25-16y-y^{2}}{-16}$$

Divide -y^{2}-16y+25 by -16.

$$x=\frac{y^{2}}{16}+y-\frac{25}{16}$$

Solve for y (complex solution)

$$y=\sqrt{16x+89}-8$$

$$y=-\sqrt{16x+89}-8$$

Solve for y

$$y=\sqrt{16x+89}-8$$

$$y=-\sqrt{16x+89}-8\text{, }x\geq -\frac{89}{16}$$