Solve y=x^4+2x^2+4y-7

$$y = x ^ { 4 } + 2 x ^ { 2 } + 4 y - 7$$

Solve for y

$$y=\frac{7-2x^{2}-x^{4}}{3}$$

Steps for Solving Linear Equation

Subtract 4y from both sides.

$$y-4y=x^{4}+2x^{2}-7$$

Combine y and -4y to get -3y.

$$-3y=x^{4}+2x^{2}-7$$

Divide both sides by -3.

$$\frac{-3y}{-3}=\frac{x^{4}+2x^{2}-7}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$y=\frac{x^{4}+2x^{2}-7}{-3}$$

Divide x^{4}+2x^{2}-7 by -3.

$$y=\frac{7-2x^{2}-x^{4}}{3}$$

Solve for x (complex solution)

$$x=i\sqrt{\sqrt{8-3y}+1}$$

$$x=-i\sqrt{\sqrt{8-3y}+1}$$

$$x=-\sqrt{\sqrt{8-3y}-1}$$

$$x=\sqrt{\sqrt{8-3y}-1}$$

Solve for x

$$x=-\sqrt{\sqrt{8-3y}-1}$$

$$x=\sqrt{\sqrt{8-3y}-1}\text{, }y\leq \frac{7}{3}$$