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Solve for c
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x^{3}+cx=y
Swap sides so that all variable terms are on the left hand side.
cx=y-x^{3}
Subtract x^{3} from both sides.
xc=y-x^{3}
The equation is in standard form.
\frac{xc}{x}=\frac{y-x^{3}}{x}
Divide both sides by x.
c=\frac{y-x^{3}}{x}
Dividing by x undoes the multiplication by x.