Solve y=x+4+2xg:xrightarrowx^2

$$y = x + 4 + 2 x g : x \rightarrow x ^ { 2 }$$

Solve for g

$$g=\frac{-x+y-4}{2}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$yx=xx+x\times 4+2xg$$

Multiply x and x to get x^{2}.

$$yx=x^{2}+x\times 4+2xg$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+x\times 4+2xg=yx$$

Subtract x^{2} from both sides.

$$x\times 4+2xg=yx-x^{2}$$

Subtract x\times 4 from both sides.

$$2xg=yx-x^{2}-x\times 4$$

Multiply -1 and 4 to get -4.

$$2xg=yx-x^{2}-4x$$

The equation is in standard form.

$$2xg=-x^{2}+xy-4x$$

Divide both sides by 2x.

$$\frac{2xg}{2x}=\frac{x\left(-x+y-4\right)}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$g=\frac{x\left(-x+y-4\right)}{2x}$$

Divide x\left(-4+y-x\right) by 2x.

$$g=\frac{y}{2}-\frac{x}{2}-2$$

Solve for x

$$x=y-2g-4$$

$$y\neq 2g+4$$