Solve y=bx^2

$$y = b x ^ { 2 }$$

Solve for b (complex solution)

$$\left\{\begin{matrix}b=\frac{y}{x^{2}}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&y=0\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bx^{2}=y$$

The equation is in standard form.

$$x^{2}b=y$$

Divide both sides by x^{2}.

$$\frac{x^{2}b}{x^{2}}=\frac{y}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$b=\frac{y}{x^{2}}$$

Solve for b

$$\left\{\begin{matrix}b=\frac{y}{x^{2}}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&y=0\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bx^{2}=y$$

The equation is in standard form.

$$x^{2}b=y$$

Divide both sides by x^{2}.

$$\frac{x^{2}b}{x^{2}}=\frac{y}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$b=\frac{y}{x^{2}}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-b^{-\frac{1}{2}}\sqrt{y}\text{; }x=b^{-\frac{1}{2}}\sqrt{y}\text{, }&b\neq 0\\x\in \mathrm{C}\text{, }&y=0\text{ and }b=0\end{matrix}\right.$$

Solve for x

$$\left\{\begin{matrix}x=\sqrt{\frac{y}{b}}\text{; }x=-\sqrt{\frac{y}{b}}\text{, }&\left(y\geq 0\text{ and }b>0\right)\text{ or }\left(y\leq 0\text{ and }b<0\right)\\x\in \mathrm{R}\text{, }&y=0\text{ and }b=0\end{matrix}\right.$$