Solve y=Ax+B

$$y = A x + B$$

Solve for A (complex solution)

$$\left\{\begin{matrix}A=-\frac{B-y}{x}\text{, }&x\neq 0\\A\in \mathrm{C}\text{, }&y=B\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$Ax+B=y$$

Subtract B from both sides.

$$Ax=y-B$$

The equation is in standard form.

$$xA=y-B$$

Divide both sides by x.

$$\frac{xA}{x}=\frac{y-B}{x}$$

Dividing by x undoes the multiplication by x.

$$A=\frac{y-B}{x}$$

Solve for A

$$\left\{\begin{matrix}A=-\frac{B-y}{x}\text{, }&x\neq 0\\A\in \mathrm{R}\text{, }&y=B\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$Ax+B=y$$

Subtract B from both sides.

$$Ax=y-B$$

The equation is in standard form.

$$xA=y-B$$

Divide both sides by x.

$$\frac{xA}{x}=\frac{y-B}{x}$$

Dividing by x undoes the multiplication by x.

$$A=\frac{y-B}{x}$$

Solve for B

$$B=y-Ax$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$Ax+B=y$$

Subtract Ax from both sides.

$$B=y-Ax$$