Solve for x_3
x_{3}=-\frac{y}{2}+4
Solve for y
y=8-2x_{3}
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8-2x_{3}=y
Swap sides so that all variable terms are on the left hand side.
-2x_{3}=y-8
Subtract 8 from both sides.
\frac{-2x_{3}}{-2}=\frac{y-8}{-2}
Divide both sides by -2.
x_{3}=\frac{y-8}{-2}
Dividing by -2 undoes the multiplication by -2.
x_{3}=-\frac{y}{2}+4
Divide y-8 by -2.
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