Solve for y
y=7\left(x-3\right)^{2}-6
Solve for x (complex solution)
x=-\frac{\sqrt{7y+42}}{7}+3
x=\frac{\sqrt{7y+42}}{7}+3
Solve for x
x=-\frac{\sqrt{7y+42}}{7}+3
x=\frac{\sqrt{7y+42}}{7}+3\text{, }y\geq -6
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y=7\left(x^{2}-6x+9\right)-6
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y=7x^{2}-42x+63-6
Use the distributive property to multiply 7 by x^{2}-6x+9.
y=7x^{2}-42x+57
Subtract 6 from 63 to get 57.
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