Solve for B
B=\frac{4x^{2}+4x-y}{3}
Solve for x (complex solution)
x=\frac{\sqrt{y+3B+1}-1}{2}
x=\frac{-\sqrt{y+3B+1}-1}{2}
Solve for x
x=\frac{\sqrt{y+3B+1}-1}{2}
x=\frac{-\sqrt{y+3B+1}-1}{2}\text{, }y\geq -3B-1
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4x^{2}+4x-3B=y
Swap sides so that all variable terms are on the left hand side.
4x-3B=y-4x^{2}
Subtract 4x^{2} from both sides.
-3B=y-4x^{2}-4x
Subtract 4x from both sides.
-3B=y-4x-4x^{2}
The equation is in standard form.
\frac{-3B}{-3}=\frac{y-4x-4x^{2}}{-3}
Divide both sides by -3.
B=\frac{y-4x-4x^{2}}{-3}
Dividing by -3 undoes the multiplication by -3.
B=\frac{4x^{2}+4x-y}{3}
Divide y-4x^{2}-4x by -3.
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