Solve y=3+1/x+1

$$y = 3 + \frac { 1 } { x + 1 }$$

Solve for x

$$x=-\frac{4-y}{3-y}$$

$$y\neq 3$$

Steps for Solving Linear Equation

Variable x cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by x+1.

$$y\left(x+1\right)=\left(x+1\right)\times 3+1$$

Use the distributive property to multiply y by x+1.

$$yx+y=\left(x+1\right)\times 3+1$$

Use the distributive property to multiply x+1 by 3.

$$yx+y=3x+3+1$$

Add 3 and 1 to get 4.

$$yx+y=3x+4$$

Subtract 3x from both sides.

$$yx+y-3x=4$$

Subtract y from both sides.

$$yx-3x=4-y$$

Combine all terms containing x.

$$\left(y-3\right)x=4-y$$

Divide both sides by y-3.

$$\frac{\left(y-3\right)x}{y-3}=\frac{4-y}{y-3}$$

Dividing by y-3 undoes the multiplication by y-3.

$$x=\frac{4-y}{y-3}$$

Variable x cannot be equal to -1.

$$x=\frac{4-y}{y-3}\text{, }x\neq -1$$

Solve for y

$$y=\frac{3x+4}{x+1}$$

$$x\neq -1$$