y = 2 x + 3 \quad \frac { x } { 6 } | \frac { y } { - 2 }
Solve for x
x=\frac{4y}{|y|+8}
Solve for y
\left\{\begin{matrix}y=\frac{8x}{4-x}\text{, }&x\geq 0\text{ and }x<4\\y=\frac{8x}{x+4}\text{, }&x>-4\text{ and }x\leq 0\end{matrix}\right.
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