Solve for x
x=3\left(y+3\right)
Solve for y
y=\frac{x-9}{3}
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\frac{1}{3}x-3=y
Swap sides so that all variable terms are on the left hand side.
\frac{1}{3}x=y+3
Add 3 to both sides.
\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y+3}{\frac{1}{3}}
Multiply both sides by 3.
x=\frac{y+3}{\frac{1}{3}}
Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.
x=3y+9
Divide y+3 by \frac{1}{3} by multiplying y+3 by the reciprocal of \frac{1}{3}.
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