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y=-3\left(x^{2}+12x+36\right)+5
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+6\right)^{2}.
y=-3x^{2}-36x-108+5
Use the distributive property to multiply -3 by x^{2}+12x+36.
y=-3x^{2}-36x-103
Add -108 and 5 to get -103.