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y=-2\left(x^{3}-9x^{2}+27x-27\right)+1
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-3\right)^{3}.
y=-2x^{3}+18x^{2}-54x+54+1
Use the distributive property to multiply -2 by x^{3}-9x^{2}+27x-27.
y=-2x^{3}+18x^{2}-54x+55
Add 54 and 1 to get 55.