Solve for y
y=12
Solve for x (complex solution)
x\in \mathrm{C}
y=12
Solve for x
x\in \mathrm{R}
y=12
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y=0\left(x-30\right)^{2}+12
Multiply 0 and 2 to get 0.
y=0\left(x^{2}-60x+900\right)+12
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-30\right)^{2}.
y=0+12
Anything times zero gives zero.
y=12
Add 0 and 12 to get 12.
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