Solve for y
y=-\left(x+2\right)^{3}+5
Solve for x
x=\sqrt[3]{5-y}-2
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y=-\left(x^{3}+6x^{2}+12x+8\right)+5
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+2\right)^{3}.
y=-x^{3}-6x^{2}-12x-8+5
To find the opposite of x^{3}+6x^{2}+12x+8, find the opposite of each term.
y=-x^{3}-6x^{2}-12x-3
Add -8 and 5 to get -3.
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