Solve y=-3/2x+4

$$y = - \frac { 3 } { 2 } x + 4$$

Solve for x

$$x=\frac{8-2y}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{3}{2}x+4=y$$

Subtract 4 from both sides.

$$-\frac{3}{2}x=y-4$$

Divide both sides of the equation by -\frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{2}x}{-\frac{3}{2}}=\frac{y-4}{-\frac{3}{2}}$$

Dividing by -\frac{3}{2} undoes the multiplication by -\frac{3}{2}.

$$x=\frac{y-4}{-\frac{3}{2}}$$

Divide y-4 by -\frac{3}{2} by multiplying y-4 by the reciprocal of -\frac{3}{2}.

$$x=\frac{8-2y}{3}$$

Solve for y

$$y=-\frac{3x}{2}+4$$