Solve for x
x=\frac{-10y-80}{3}
Solve for y
y=-\frac{3x}{10}-8
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-\frac{3}{10}x-8=y
Swap sides so that all variable terms are on the left hand side.
-\frac{3}{10}x=y+8
Add 8 to both sides.
\frac{-\frac{3}{10}x}{-\frac{3}{10}}=\frac{y+8}{-\frac{3}{10}}
Divide both sides of the equation by -\frac{3}{10}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+8}{-\frac{3}{10}}
Dividing by -\frac{3}{10} undoes the multiplication by -\frac{3}{10}.
x=\frac{-10y-80}{3}
Divide y+8 by -\frac{3}{10} by multiplying y+8 by the reciprocal of -\frac{3}{10}.
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