Solve for x
x=\frac{8\left(y-6\right)}{9}
Solve for y
y=\frac{9x}{8}+6
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y=-\frac{1}{8}x\left(-9\right)+6
Anything divided by one gives itself.
y=\frac{9}{8}x+6
Multiply -\frac{1}{8} and -9 to get \frac{9}{8}.
\frac{9}{8}x+6=y
Swap sides so that all variable terms are on the left hand side.
\frac{9}{8}x=y-6
Subtract 6 from both sides.
\frac{\frac{9}{8}x}{\frac{9}{8}}=\frac{y-6}{\frac{9}{8}}
Divide both sides of the equation by \frac{9}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y-6}{\frac{9}{8}}
Dividing by \frac{9}{8} undoes the multiplication by \frac{9}{8}.
x=\frac{8y}{9}-\frac{16}{3}
Divide y-6 by \frac{9}{8} by multiplying y-6 by the reciprocal of \frac{9}{8}.
y=-\frac{1}{8}x\left(-9\right)+6
Anything divided by one gives itself.
y=\frac{9}{8}x+6
Multiply -\frac{1}{8} and -9 to get \frac{9}{8}.
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Limits
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