Solve for y
y=x^{2}+1
Solve for x (complex solution)
x=-\sqrt{y-1}
x=\sqrt{y-1}
Solve for x
x=\sqrt{y-1}
x=-\sqrt{y-1}\text{, }y\geq 1
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y=x^{2}-2x+1+2x
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
y=x^{2}+1
Combine -2x and 2x to get 0.
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