Solve for y
y=25\left(x-2\right)^{2}
Solve for x (complex solution)
x=-\frac{\sqrt{y}}{5}+2
x=\frac{\sqrt{y}}{5}+2
Solve for x
x=-\frac{\sqrt{y}}{5}+2
x=\frac{\sqrt{y}}{5}+2\text{, }y\geq 0
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y=25x^{2}-100x+100
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(5x-10\right)^{2}.
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