Solve for y
y=2+12x-25x^{2}
Solve for x (complex solution)
x=\frac{-\sqrt{86-25y}+6}{25}
x=\frac{\sqrt{86-25y}+6}{25}
Solve for x
x=\frac{-\sqrt{86-25y}+6}{25}
x=\frac{\sqrt{86-25y}+6}{25}\text{, }y\leq \frac{86}{25}
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y=2x+3-\left(25x^{2}-10x+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(5x-1\right)^{2}.
y=2x+3-25x^{2}+10x-1
To find the opposite of 25x^{2}-10x+1, find the opposite of each term.
y=12x+3-25x^{2}-1
Combine 2x and 10x to get 12x.
y=12x+2-25x^{2}
Subtract 1 from 3 to get 2.
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