Solve y=sqrt{1-5x}

$$y = \sqrt { 1 - 5 x }$$

Solve for x

$$x=\frac{1-y^{2}}{5}$$

$$y\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{1-5x}=y$$

Square both sides of the equation.

$$-5x+1=y^{2}$$

Subtract 1 from both sides of the equation.

$$-5x+1-1=y^{2}-1$$

Subtracting 1 from itself leaves 0.

$$-5x=y^{2}-1$$

Divide both sides by -5.

$$\frac{-5x}{-5}=\frac{y^{2}-1}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$x=\frac{y^{2}-1}{-5}$$

Divide y^{2}-1 by -5.

$$x=\frac{1-y^{2}}{5}$$

Solve for x (complex solution)

$$x=\frac{1-y^{2}}{5}$$

$$arg(y)<\pi \text{ or }y=0$$

Solve for y

$$y=\sqrt{1-5x}$$

$$x\leq \frac{1}{5}$$