Solve for x
x=3y+7
Solve for y
y=\frac{x-7}{3}
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y=\frac{1}{3}x-\frac{7}{3}
Divide each term of x-7 by 3 to get \frac{1}{3}x-\frac{7}{3}.
\frac{1}{3}x-\frac{7}{3}=y
Swap sides so that all variable terms are on the left hand side.
\frac{1}{3}x=y+\frac{7}{3}
Add \frac{7}{3} to both sides.
\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y+\frac{7}{3}}{\frac{1}{3}}
Multiply both sides by 3.
x=\frac{y+\frac{7}{3}}{\frac{1}{3}}
Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.
x=3y+7
Divide y+\frac{7}{3} by \frac{1}{3} by multiplying y+\frac{7}{3} by the reciprocal of \frac{1}{3}.
y=\frac{1}{3}x-\frac{7}{3}
Divide each term of x-7 by 3 to get \frac{1}{3}x-\frac{7}{3}.
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